Simplification Questions for SSC CGL with Solutions

Simplification Questions for SSC CGL

Quantitative aptitude is a crucial section in the SSC CGL Exam, with 30 questions asked from this section in the SSC CGL Tier II examination. Out of these, 2-3 questions typically come from the topic of simplification, which are usually time-consuming. Regular practice is essential for mastering these questions. When the examiner want to include time-consuming questions, he usually chooses this topic. To help candidates in their preparation, we have shared simplification questions for practice, as the SSC CGL Tier II examination is scheduled in December 2024.

Q1. (310 + 10 + 332 + 10 + 550 – 20 + 915) ÷ (20 + 22 – x + 18) = 43, Find the value of x?
(a) 11
(b) 15
(c) 18
(d) 20

Q2. What is the simplified value of:
1/8 × {(x-1/y)²– (x+1/y)²}

(a) y/x
(b) -2x/y
(c) -x/2y
(d) -x/y

Q3. What is the simplified value of

Q4. Find the value of the following expression:

Q5. Find the value of the following expression:

(a) 8.92
(b) 6.25
(c) 4.55
(d) 5.20

Q6. The value of 768 ÷ 8 of 6 × [126 ÷ 9 × (19 – 5) of 26 – (9 – 4)] ÷ 3 is:
(a) 76,281
(b) 27,152
(c) 67,162
(d)17,620

Q7. The value of 90 ÷ 5 of 9 × [39 ÷ 13 × (6 – 3)] – (90 ÷ 3 of 15) is:

(a) 78
(b) 91
(c) 17
(d) 16

Q8. Simplified: 75 of 3 + (49 7) 6 + 105 ÷ 15 of 7.

(a) 452
(b) 189
(c) 152
(d) 268

Q.9 The value of 18÷9×4+36 of 6÷1-42 is:
(a) 186
(b) 182
(c) 189
(d) 282

Q10. If (640 + 684 + 1060 + 1830) ÷ (40 + 44 – 2x + 36) = 43, then the value of x is?
(a) 11
(b) 13
(c) 15
(d) 17

SSC CGL Simplification Question Solutions

Below, we have provided the best possible solutions for these simplification questions. However, aspirants are advised to first attempt solving the questions on their own and then check where they made mistakes. To solve these problems faster, candidates should remember cubes (1-30), multiplication tables up to 30, and the BODMAS rule. Additionally, using the digital sum method can help speed up calculations.

S1. Ans.(a)
Sol.

⟹ (320 + 342 + 530 + 915) ÷ (20 + 22 – x + 18) = 43
⟹ 2107= 43 × (60-x)
⟹ x = 60 – 49
⟹ x = 11

S2. Ans.(c)
Sol.

S3. Ans.(b)
Sol.

S4.Ans.(b)
Sol.

S5.Ans.(c)
Sol.

S6. Ans.(b)
Sol.
⟹ 768 ÷ 8 of 6 × [126 ÷ 9 × (19 – 5) of 26 – (9-4)] ÷ 3
⟹ 768 ÷ 48 × [14 × 364 – 5] ⟹ 16 × 5091 ÷ 3 = 16 × 1697 = 27152

S7. Ans.(d)
Sol.
⟹ 90 ÷ 5 of 9 × [13 ÷ 13 × (6 – 3)] – (90 ÷ 3 of 15)
⟹ 2 × [3 × 3] – [2] ⟹ 2 × 3 × 3 – 2 = 16

S8. Ans.(d)
Sol.

⟹ 75 of 3 + (49 ÷ 7) × 6 + 105 ÷ 15 of 7
⟹ 225 + 7 × 6 + 1
⟹ 225 + 42 + 1 = 268

S9. Ans.(b)
Sol.

⟹ 18 ÷ 9 × 4 + 36 of 6 ÷ 1 – 42
⟹ 2 × 4 + 216 – 42
⟹ 224 – 42 = 182

S10. Ans.(a)

Sol.