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The RRB NTPC Geometry Question with Solution PDF is a must-have resource for all the eligible candidates of the RRB NTPC Examination. We have provided some 20 important RRB NTPC Geometry Questions with Solution PDFs below for students for their effective preparation. Through this article, candidates will develop an understanding of the type of questions asked in the examination, and key concepts to build strategy and improve problem-solving skills. Download the given solution PDF and boost your confidence!
Geometry Questions for RRB NTPC
Q1. In ∆ABC, angle BAC = 90°. If BC = 30 cm, then what is the length of the median AD?
(a) 20 cm
(b) 15 cm
(c) 18 cm
(d) 19 cm
Q3. How many isosceles ∆ with integer sides are possible in which the sum of two sides is 14 cm?
(a) 25
(b) 24
(c) 21
(d) 22
Q6. In ∆LMN, LM = LN, and K is a point on MN, if MK = 4 cm, LM = 11 cm, and LK = 8 cm, then the length of NK is?
(a) 14.25 cm
(b) 16 cm
(c) 18 cm
(d) 12 cm
Q7. The measure of sides (x² – 1), (x² + 1) and 2x cm. Then find the triangle is :
(a) Obtuse triangle
(b) Right angle triangle
(c) Isosceles triangle
(d) Scalene triangle
Q8. The inradius of a triangle is 12 cm and the sum of the length of its side is 100 cm. Find the area of the triangle.
(a) 500 cm²
(b) 300 cm²
(c) 400 cm²
(d) 600 cm2
Q11. A circle is inscribed in a triangle ABC. It touches sides AB, BC, and AC at points R, P, and Q, respectively. It AQ 7 cm, PC 6 cm, and BR 8 cm, then the perimeter of the triangle is:
(a) 42cm
(b) 50cm
(c) 25cm
(d) 45cm
Q13. ABDC is a trapezium in which AB||DC and AB = 8cm, BD = 10cm, CD = 12cm, AC = 16cm, then AD² + BC² is equal to.
(a) 530 cm²
(b) 548 cm²
(c) 624 cm²
(d) 630 cm²
Q14. Number of sides of two regular polygons are in the ratio 3 : 4 and each of their interior angle are in the ratio 8 : 9. The number of sides of the two polygons are .
(a) 8, 12
(b) 4, 8
(c) 6, 15
(d) 6, 8
Q17. In ∆PQR, = 90°, PQ = 24 cm and PR = 18 cm. S is the mid-point of PR and ST at T. What is the area of ∆RST?
(a) 18.35cm2
(b) 17.25cm2
(c) 19.44cm2
(d) 15.67cm2
Q18. O is the incentre of ∆PQR. If ∠QOR = 108°, then ∠P = ?
(a) 380
(b) 560
(c) 450
(d) 360
Q20. AB is a chord in a circle with center O. AB is produced to C such that BC is equal to the radius of the circle. C is joined to O and produced to meet the circle at D. if ACD = 40°, then the measure of AOD is-
(a) 130°
(b) 125°
(c) 138°
(d) 120°
Geometry Questions for RRB NTPC with Solution PDF
Provided below is a solution PDF to go through for a better understanding of students. By going through the solutions, students can strengthen their knowledge and boost confidence. Candidates must refer to the below RRB NTPC Geometry Questions Solutions PDF